Code:
public class Main
{
//calculateLength() will count the digits present in a number
public static int calculateLength(int n){
int length = 0;
while(n != 0){
length = length + 1;
n = n/10;
}
return length;
}
public static void main(String[] args) {
int num = 175, sum = 0, rem = 0, n;
int len = calculateLength(num);
//Makes a copy of the original number num
n = num;
//Calculates the sum of digits powered with their respective position
while(num > 0){
rem = num%10;
sum = sum + (int)Math.pow(rem,len);
num = num/10;
len--;
}
//Checks whether the sum is equal to the number itself
if(sum == n)
System.out.println(n + " is a disarium number");
else
System.out.println(n + " is not a disarium number");
}
}
Output:
Tags:
Java Programs
